BHU PMT BHU PMT (Mains) Solved Paper-2010

  • question_answer
    A large open tank has two holes in the wall. One is a square hole of side L at a depth y from the top and the other is a circular hole of radius R at a depth 4y from the top. When the tank is completely filled with water, the quantities of water flowing out per second from both holes are the same. Then, R is equal to

    A)  \[\frac{L}{\sqrt{2\pi }}\]                              

    B)  \[2\pi L\]

    C)  \[L\]                                     

    D)  \[\frac{L}{2\pi }\]

    Correct Answer: A

    Solution :

                     Velocity of efflux, \[v=\sqrt{2gh}\] where, h denotes the depth of the hole. The quantities of water flowing put per second from both holes are given to be the same \[{{A}_{1}}{{v}_{1}}={{A}_{2}}{{v}_{2}}\] \[{{(L)}^{2}}\sqrt{2gy}=(\pi {{R}^{2}})\sqrt{2g(4y)}\]                 \[{{(L)}^{2}}=2\pi {{R}^{2}}\]                 \[R=\frac{L}{\sqrt{2\pi }}\]


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