Directions : In the following question more than one of the answers given may be correct. Select the correct answer and mark it according to the code:
On mixing a certain alkane with chlorine and irradiating it with ultraviolet light, it forms two monochloro derivatives. The alkane could be (1) propane (2) pentane (3) iso-butane (4) neo-pentaneA) 1, 2 and 3 are correct.
B) 1 and 2 are correct.
C) 2 and 4 are correct.
D) 1 and 3 are correct.
Correct Answer: D
Solution :
Two types of hydrogen containing alkane gives two monochloro derivatives. (1) \[\underset{propane}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{3}}}}\,\xrightarrow[UV\,light]{C{{l}_{2}}}C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Cl\] \[+C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}}\] (2) \[\underset{pen\tan e}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}c{{H}_{3}}}}\,\xrightarrow[UV\,litght]{C{{l}_{2}}}\] \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}Cl+\] \[C{{H}_{3}}C{{H}_{2}}\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\mathop{CH}}\,-{{C}_{2}}{{H}_{5}}+C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}}\](3) \[\underset{iso-bu\tan e}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}}}}\,\xrightarrow[UV\,llight]{C{{l}_{2}}}\] \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{2}}Cl+C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} Cl \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{3}}\] (4) \[\underset{neo-pen\tan e}{\mathop{{{H}_{3}}C-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{3}}}}\,\xrightarrow[UV\,light]{C{{l}_{2}}}\] \[{{H}_{3}}C-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{2}}Cl \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{3}}\] \[\therefore \]Only propane and iso-butane gives two onochloro derivatives.
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