The equivalent capacity between the points\[X\]and Y in the circuit with\[C=1\text{ }\mu F\]is
A) \[2\mu F\]
B) \[3\mu F\]
C) \[1\mu F\]
D) \[0.5\mu F\]
Correct Answer:
A
Solution :
The circuit is shown in the figure. As points a and b are at same potential, so no charge flows through ab. Now two remaining capacitors are in parallel, hence \[{{C}_{eq}}=C+C=2C\] \[=2\times 1=2\mu F\]