BHU PMT BHU PMT (Mains) Solved Paper-2008

  • question_answer
    Three charges\[1\mu C,1\mu C\]and\[2\mu C\]are kept at the vertices A, B and C of an equilateral triangle force on the charge at C is

    A)  0.9 N                                    

    B)  1.8 N

    C)  2.72 N                 

    D)  3.6 N

    Correct Answer: D

    Solution :

                     The situation is shown in figure. Force on C due to A \[{{F}_{AC}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{A}}{{q}_{C}}}{r_{AC}^{2}}\]                 \[=\frac{9\times {{10}^{9}}\times 1\times 2\times {{10}^{-12}}}{{{(0.1)}^{2}}}=1.8N\] Similarly, \[{{F}_{BC}}=1.8\,N\] Hence, net force on                 \[C={{F}_{AC}}+{{F}_{BC}}=3.6\,N\]


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