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BHU PMT BHU PMT (Mains) Solved Paper-2006

  • question_answer
    0.45 g acid of molecular weight 90 was neutralise by 20 mL of 0.5N KOH. The basicity of the acid is:

    A)  2                                            

    B)  4

    C)  1                                            

    D)  3

    Correct Answer: A

    Solution :

                     Gram equivalent of acid = gram equivalent of \[KOH\] \[\frac{0.45}{E}=\frac{20\times 0.5}{1000}\] \[E=45\] \[Equivalent\text{ }weight=\frac{molecular\text{ }weight}{basicity}\] \[Basicity=\frac{90}{45}=2\]


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