BHU PMT BHU PMT (Mains) Solved Paper-2006

  • question_answer
    The ratio between the root mean square velocity of\[{{H}_{2}}\]at 100 K and that of\[{{O}_{2}}\]at 1600 K is:

    A)  \[1:\sqrt{2}\]                                   

    B)  \[\sqrt{2}:1\]

    C)  \[1:3\]                                 

    D)  \[2:1\]

    Correct Answer: B

    Solution :

                     \[\because \]    \[\mu =\sqrt{\frac{3RT}{M}}\] \[\therefore \]  \[\frac{{{\mu }_{H}}}{{{\mu }_{O}}}={\sqrt{\frac{3R{{T}_{H}}}{{{M}_{H}}}}}/{\sqrt{\frac{100\times 32}{800\times 2}}}\;=\sqrt{\frac{2}{1}}\]                 \[\frac{{{\mu }_{H}}}{{{\mu }_{O}}}=\sqrt{\frac{2}{1}}\] \[{{\mu }_{H}}:{{\mu }_{O}}=\sqrt{2}:1\]


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