A) 60 min
B) 30 min
C) 90 min
D) 15 min
Correct Answer: A
Solution :
\[k=\frac{2.303}{t}\log \frac{{{N}_{0}}}{N}\] \[=\frac{2.303}{20}\log \frac{1}{1-\frac{3}{4}}=\frac{2.303}{120}\log 4\] \[=0.0116\text{ }mi{{n}^{-1}}\] \[{{t}_{1/2}}=\frac{0.693}{k}=\frac{0.693}{0.0116}=60\,\min \]
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