A) 100
B) 200
C) 4
D) \[\frac{1}{4}\]
Correct Answer: D
Solution :
\[{{r}_{m}}=\left( \frac{{{m}^{2}}}{z} \right)(0.53{\AA})=(r\times 0.53{\AA})\] \[\therefore \] \[\frac{{{m}^{2}}}{z}=n\] Here\[m=5\]for\[_{100}F{{m}^{257}}\] (the outermost shell) and\[z=100\] \[\therefore \] \[n=\frac{{{(5)}^{2}}}{100}=\frac{1}{4}\]You need to login to perform this action.
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