A) \[24\,\,\Omega \]
B) \[48\,\,\Omega \]
C) \[12\,\,\Omega \]
D) \[36\,\,\Omega \]
Correct Answer: B
Solution :
In case of galvanometer, \[I\propto \theta \] So, \[\frac{{{I}_{G}}}{I}=\frac{10}{50}=\frac{1}{5}\]i.e., \[{{I}_{G}}=\frac{1}{5}I\] Now as in case of a shunted galvanometer as shown \[(I-{{I}_{G}})S={{I}_{G}}G\] i.e., \[\left( I-\frac{1}{5}I \right)\times 12=\frac{1}{2}{{I}_{G}}\] \[\therefore \] \[G=4\times 12=48\,\Omega \]You need to login to perform this action.
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