Directions : In the following question more than one of the answers given may be correct. Select the correct answer and mark it according to the code:
Goemetrical isomerism is shown by: (1) \[{{C}_{2}}{{H}_{2}}C{{l}_{2}}\] (2) \[{{C}_{2}}{{H}_{5}}NO\] (3) \[C{{H}_{3}}CH==C{{H}_{2}}\] (4) \[C{{H}_{3}}C{{H}_{2}}OH\]A) 1, 2 and 3 are correct
B) 1 and 2 are correct
C) 2 and 4 are correct
D) 1 and 3 are correct
Correct Answer: B
Solution :
Geometrical isomerism is shown by\[{{C}_{2}}{{H}_{2}}C{{l}_{2}}\] and\[{{C}_{2}}{{H}_{5}}NO\]. \[{{C}_{2}}{{H}_{2}}C{{l}_{2}}:\] \[\underset{Cis}{\mathop{\underset{H-C-Cl}{\overset{H-C-Cl}{\mathop{|\,|}}}\,}}\,\] \[\underset{trans}{\mathop{\underset{Cl-C-H}{\overset{H-C-Cl}{\mathop{|\,|}}}\,}}\,\] \[{{C}_{2}}{{H}_{5}}NO:\] \[\underset{syn}{\mathop{\underset{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,N-OH}{\overset{C{{H}_{3}}-C-H}{\mathop{|\,|}}}\,}}\,\] \[\underset{anti}{\mathop{\underset{OH-N}{\overset{C{{H}_{3}}-C-H}{\mathop{|\,|}}}\,}}\,\]
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