A) \[4,\text{ }3,\text{ }2,+\frac{1}{2}\]
B) \[4,\text{ }2,\text{ }1,\text{ }0\]
C) \[4,\text{ }3,\text{ }-2,+\frac{1}{2}\]
D) \[4,\text{ }2,\text{ }1,-\frac{1}{2}\]
Correct Answer: D
Solution :
For 4d electrons: \[n=4,\]for d sub-shell\[l=2\] Hence, m can be\[-2,\text{ }-1,\text{ }0\text{ }+1,\text{ }+2\]and s either\[+\frac{1}{2}\]and\[-\frac{1}{2}\]
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