BHU PMT BHU PMT (Mains) Solved Paper-2005

  • question_answer
    The frequency of yellow light having wavelength 600 nm is:

    A)  \[5\times {{10}^{14}}Hz\]           

    B) \[5\times {{10}^{17}}Hz\]

    C)  \[2.5\times {{10}^{14}}Hz\]       

    D) \[2.5\times {{10}^{7}}Hz\]

    Correct Answer: A

    Solution :

                     \[\lambda =600\text{ }nm=600\times {{10}^{-9}}m=6\times {{10}^{-7}}m\] \[c=3\times {{10}^{8}}m/s\] \[v=\frac{c}{\lambda }=\frac{3\times {{10}^{8}}}{6\times {{10}^{-7}}}\] \[=5\times {{10}^{14}}Hz\]


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