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BHU PMT BHU PMT (Mains) Solved Paper-2005

  • question_answer
    An aqueous solution freezes at\[-0.186{}^\circ C,\] what is the elevation in boiling point? \[({{k}_{f}}=1.86,{{k}_{b}}=0.512)\]

    A)  0.186                                   

    B)  0.512

    C)   0.0512                                

    D)  0.86

    Correct Answer: C

    Solution :

                     \[\because \]    \[\Delta {{T}_{f}}={{k}_{f}}\times m\] \[0.186=1.86\times m\] \[m=0.1\] Now,    \[\Delta {{T}_{b}}={{K}_{b}}\times m\] \[=0.512\times 0.1\] \[=0.512{}^\circ C\]


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