A) \[NO_{3}^{-}\]
B) \[SO_{3}^{2-}\]
C) \[BO_{3}^{3-}\]
D) \[CO_{3}^{2-}\]
Correct Answer: B
Solution :
In\[SO_{3}^{2-}\]d-orbifal of S atom overlaps with p-orbital of O-atom to form a Ti-bond hence, \[SO_{3}^{2-}\]has\[p\pi -d\pi \]bonding.
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