A) \[2C{{H}_{3}}N{{H}_{2}}+C{{H}_{3}}COOH\]
B) \[2C{{H}_{3}}OH+C{{H}_{3}}CON{{H}_{2}}\]
C) \[{{(C{{H}_{3}})}_{2}}NH+C{{H}_{3}}COOH\]
D) \[{{(C{{H}_{3}})}_{2}}NCOOH+C{{H}_{4}}\]
Correct Answer: C
Solution :
\[{{(C{{H}_{3}})}_{2}}NCOC{{H}_{3}}\]on refluxing with acid gives dimethylamine and acetic acid. \[{{(C{{H}_{3}})}_{2}}\underset{\begin{smallmatrix} \\ H \end{smallmatrix}}{\mathop{N}}\,-\underset{\begin{smallmatrix} \\ OH \end{smallmatrix}}{\mathop{CO}}\,C{{H}_{3}}\xrightarrow[{}]{Acid}{{(C{{H}_{3}})}_{2}}NH\] \[+C{{H}_{3}}COOH\]
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