A) 1 g
B) 1.5 g
C) 2g
D) 2.5g
Correct Answer: B
Solution :
We know that\[m=zIt=z\frac{V}{R}t\] \[\therefore \] \[\frac{{{m}_{1}}}{{{m}_{2}}}=\frac{{{V}_{1}}{{t}_{1}}}{{{V}_{2}}{{t}_{2}}}\] Or \[{{m}_{2}}=\frac{{{V}_{2}}{{t}_{2}}}{{{V}_{1}}{{t}_{1}}}\times {{m}_{1}}\] \[\therefore \] \[{{m}_{2}}=\frac{6\times 45}{12\times 30}\times 2\] \[=1.5\,g\]
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