BHU PMT BHU PMT (Mains) Solved Paper-2005

  • question_answer
    Certain neutron stars (extremely dense stars) are believed to be rotating at about 1 rev/s. If such a star has a radius of 20 km, the acceleration of an object on the equator of the star will be:

    A) \[20\times {{10}^{3}}m/{{s}^{2}}\]          

    B) \[120\times {{10}^{3}}m/{{s}^{2}}\]

    C)  \[8\times {{10}^{5}}m/{{s}^{2}}\]           

    D) \[4\times {{10}^{8}}m/{{s}^{2}}\]

    Correct Answer: C

    Solution :

                     Acceleration \[={{\omega }^{2}}r={{(2\pi f)}^{2}}r=4{{\pi }^{2}}{{f}^{2}}r\] \[=4{{\pi }^{2}}\times 1\times (2\times {{10}^{4}})\] \[=8\times {{10}^{5}}m/{{s}^{2}}\]


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