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BCECE Medical BCECE Medical Solved Papers-2012

  • question_answer
    If a stone is projected from ground with a velocity \[50\,m{{s}^{-1}}\] and at an angle of \[{{30}^{o}}\], it takes 3 s to cross a wall. How far beyond the wall the stone will strike the ground? (Take \[g=10\,\,m{{s}^{-2}}\])

    A)  50.5 m         

    B)  91.5 m

    C)  86.6 m         

    D)  100 m 

    Correct Answer: C

    Solution :

    Total time of flight                 \[=\frac{2u\sin \theta }{g}=\frac{2\times 50\times 1}{2\times 10}=5\,s\] Time to cross the wall = 3 s \[\therefore \] Time in air after crossing the wall                 = (5 - 3) = 2 s So, distance travelled beyond the wall                 \[=(u\cos \theta )\,t\] \[=50\times \frac{\sqrt{3}}{2}\times 2=86.6\,m\]


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