A) 18.89V
B) 3V
C) 15V
D) 9.42V
Correct Answer: D
Solution :
Induced emf \[e=\pi {{l}^{2}}Bn=\frac{{{l}^{2}}B\omega }{2}\] \[=\frac{{{(1.0)}^{2}}\times 0.25\times 2\times 3.14\times 12}{2}=9.42\,V\]You need to login to perform this action.
You will be redirected in
3 sec