A) \[\frac{10}{28}\]cm
B) \[\frac{10}{14}\]cm
C) \[\frac{10}{7}\]mm
D) 0.7 cm
Correct Answer: C
Solution :
\[2Tl=\pi {{r}^{2}}ld\times g\] \[r=\sqrt{\left( \frac{2\,T}{\pi dg} \right)}=\sqrt{\frac{2\times 44\times 7}{22\times 1.4\times 980}}\] \[=\frac{1}{7}cm=\frac{10}{7}\,mm\]
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