A) \[\frac{1}{{{a}^{n-1}}}\]
B) \[{{a}^{n+1}}\]
C) \[{{a}^{n-1}}\]
D) \[\frac{1}{{{a}^{n}}}\]
Correct Answer: A
Solution :
\[{{t}_{1/2}}\propto \frac{1}{{{a}^{n-1}}}\] where, \[{{t}_{1/2}}=\] half-life period a = initial concentration n = order of the reaction
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