A) \[-\frac{Q}{2}\]
B) \[-\frac{Q}{4}\]
C) \[+\frac{Q}{4}\]
D) \[+\frac{Q}{2}\]
Correct Answer: B
Solution :
For equilibrium of Q \[\frac{Qq}{4\pi {{\varepsilon }_{0}}{{\left( \frac{l}{2} \right)}^{2}}}+\frac{{{Q}^{2}}}{4\pi \,{{\varepsilon }_{0}}\,{{l}^{2}}}=0\]You need to login to perform this action.
You will be redirected in
3 sec