BCECE Medical BCECE Medical Solved Papers-2010

  • question_answer
    Two resistors \[400\,\,\Omega \]. And \[800\,\,\Omega \] are connected in series with a 6 V battery. The potential difference measured by voltmeter of\[10\,\,\Omega \] across \[400\,\,\Omega \] resistor is

    A)  2 V              

    B)  1.95V

    C)  3.8V            

    D)  4V

    Correct Answer: B

    Solution :

    Here, the resistances of \[400\,\,\Omega \], and \[10000\,\,\Omega \] are in parallel, their effective resistance \[{{R}_{p}}\] will be                 \[{{R}_{p}}=\frac{400\times 10000}{400+10000}\]                 \[=\frac{5000}{13}\,\Omega \] Total resistance of the circuit,                 \[=\frac{5000}{13}+800=\frac{15400}{13}\Omega \] Current in the circuit                 \[i=\frac{6}{15400/13}=\frac{39}{7700}A\] Potential difference across voltmeter                 \[=i{{R}_{p}}\] \[\frac{39}{7700}\times \frac{5000}{13}=1.95\,V\]


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