2. Solved Papers
  3. BCECE Medical

BCECE Medical BCECE Medical Solved Papers-2007

  • question_answer
    \[_{7}{{N}^{14}}\] is bombarded with \[_{2}H{{e}^{4}}\]. The resulting nucleus is \[_{8}{{O}^{17}}\] with the emission of

    A)  neutrino       

    B)  antineutrino

    C)  proton         

    D)  neutron

    Correct Answer: C

    Solution :

    Key Idea: Mass number and atomic number in nuclear reactions are conserved. The nuclear reaction is as follows.                 \[_{7}{{N}^{14}}{{+}_{2}}H{{e}^{4}}{{\xrightarrow{{}}}_{8}}{{O}^{17}}{{+}_{q}}{{X}^{p}}\] Conservation of mass number, gives                 \[p=14+4-17=1\] Conservation of atomic number gives                 \[q=7+2-8=1\] Hence, particle is a proton \[_{1}{{H}^{1}}\].


You need to login to perform this action.
You will be redirected in 3 sec spinner