BCECE Medical BCECE Medical Solved Papers-2006

  • question_answer
    A charge situated at a certain distance along the axis of an electric dipole experiences a force F. If the distance of the charge from the dipole is doubled, the force acting on it will become :

    A)  \[2\,F\]

    B)  \[\frac{F}{2}\]

    C)  \[\frac{F}{4}\]

    D)  \[\frac{F}{8}\]

    Correct Answer: D

    Solution :

    The electric field at a point distance r from electric dipole is                 \[E=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{p}{{{r}^{3}}}\] or            \[E\propto \frac{1}{{{r}^{3}}}\] where, p is dipole moment and r is distance of point from centre of dipole. Force on that point is                 \[F=EQ\] or            \[F\propto \frac{1}{{{r}^{3}}}\] or            \[\frac{{{F}_{2}}}{{{F}_{1}}}={{\left( \frac{{{r}_{1}}}{{{r}_{2}}} \right)}^{3}}\] or            \[\frac{{{F}_{2}}}{{{F}_{1}}}={{\left( \frac{r}{2\,r} \right)}^{3}}\] or            \[\frac{{{F}_{2}}}{F}=\frac{1}{8}\] \[\therefore \] \[{{F}_{2}}=\frac{F}{8}\]


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