A) 100 V
B) 0.2V
C) 440V
D) 40V
Correct Answer: A
Solution :
emf induced in coil is given by \[e=-L\frac{\Delta i}{\Delta t}\] ?. (i) Given, \[L=40\,mH=40\times {{10}^{-3}}H\], \[\Delta i=11-1=10A\] \[\Delta t=4\,ms=4\times {{10}^{-3}}s\] Putting the values in Eq. (i), we obtain \[\left| e \right|=40\times {{10}^{-3}}\times \frac{10}{4\times {{10}^{-3}}}=100\,V\] Note: The minus sign in the Eq. (i) is the reflection of Lenzs law.
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