BCECE Medical BCECE Medical Solved Papers-2001

  • question_answer
    An atom of mass number A and atomic number Z emits successively an \[\alpha \]-particle and a, \[\beta \]-particle and y-rays. The mass number and atomic number of the end product, will be :

    A)  A - 4, Z - 1  

    B)  A - 4, Z - 2

    C)  A - 1, Z - 4

    D)  A, Z + 1

    Correct Answer: A

    Solution :

    After emission of an \[\alpha \]-particle, the mass number reduces by 4 unit and atomic number by 2 unit. \[\beta \]-emission cause 1 unit increase in atomic number, \[\gamma \]-emission cause no effect on mass number and atomic number. Thus, the reaction can be shown assuming the element\[_{Z}^{A}X\]as the parent nucleus. \[_{Z}^{A}X\xrightarrow{\alpha }_{Z}^{A}_{-2}^{-4}Y\xrightarrow{\beta }_{Z}^{A}_{-1}^{-4}M\xrightarrow{\gamma }_{Z}^{A}_{-1}^{-4}M\] Hence, atomic number and mass number of daughter nucleus are Z-1 and A - 4 respectively.


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