A) \[-\text{ 767 kJ}/\text{mol}\]
B) \[~\text{767 kJ}/\text{mol}\]
C) \[-\text{392 kJ}/\text{mol}\]
D) \[\text{392 kJ}/\text{mol}\]
Correct Answer: C
Solution :
\[Mg(s)+C{{l}_{2}}(g)\to MgC{{l}_{2}}(s),\] \[\Delta {{H}_{1}}=-642kJ/\text{mole}\] \[Mg(s)+\frac{1}{2}C{{l}_{2}}(g)\to MgCl(s),\] \[\Delta {{H}_{2}}=-125\text{kJ/mol}\] \[2MgCl\to MgC{{l}_{2}}+Mg,\] \[\Rightarrow \] \[\Delta H=\Delta {{H}_{1}}-2\Delta {{H}_{2}}\] \[=-642-2\times (-125)=-392\text{kJ/mol}\]
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