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BCECE Engineering BCECE Engineering Solved Paper-2015

  • question_answer
    Argon crystallises in fee arrangement and the density of solid and liquid at is \[\text{1}.\text{59 g}/\text{c}{{\text{m}}^{\text{3}}}\]and\[\text{1}.\text{42 g}/\text{c}{{\text{m}}^{\text{3}}},\], respectively. The percentage of empty space in liquid at is

    A) 34.84%

    B)                 43.8% 

    C) 23.4%                   

    D) 21.6%

    Correct Answer: A

    Solution :

    Let the volume of solid \[\text{Ar }=\text{ 1}00\text{ mL}\] Mass of solid \[Ar=V\times \rho =100\times 1.59g/c{{m}^{3}}\] \[=159g\] Volume of liquid Ar \[=\frac{Mass}{\rho }=\frac{159g}{1.4gc{{m}^{-3}}}\] \[=11.357\text{ml}\] \[\because \] Ar crystallizes in fcc type lattice, the packing fraction \[=0.74\] Actual volume occupied by Ar \[\text{= Packing fraction }\!\!\times\!\!\text{ Volume of solid Ar}\]\[\text{= 0}\text{.74 }\!\!\times\!\!\text{ 100 =74 mL}\] \[\therefore \]% empty space in liquid \[Ar=\frac{(11357-74)\times 100}{113.57}\] \[=34.84%\]


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