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BCECE Engineering BCECE Engineering Solved Paper-2015

  • question_answer
    The reaction between nitric oxide \[\left( \text{NO} \right)\] and oxygen to form nitrogen dioxide \[\left( \text{N}{{\text{O}}_{2}} \right)\] is a key step in                 photochemical smog formation \[\text{2NO(g)+}{{\text{O}}_{\text{2}}}\text{(g)}\to \text{2N}{{\text{O}}_{\text{2}}}\text{(g)}\]  The grams of \[\text{N}{{\text{O}}_{\text{2}}}\]are formed by complete by reaction of \[\text{1}.\text{2}0\text{ g}\] of NO is

    A) 7.2g

    B) 2.3g  

    C) 1.8g  

    D) 4.1 g

    Correct Answer: C

    Solution :

    1 mole of NO gives = 1 mol \[N{{O}_{2}}\] Hence, mol gives \[\text{1}\text{.20 g NO=}\frac{\text{1}\text{.20}}{\text{30}}\text{mol}\] gives \[\text{=1 }\!\!\times\!\!\text{ }\frac{\text{1}\text{.20}}{\text{30}}\text{mol N}{{\text{O}}_{\text{2}}}\text{=}\frac{\text{1}\text{.20}}{\text{30}}\text{ }\!\!\times\!\!\text{ 46 g N}{{\text{O}}_{\text{2}}}\text{=1}\text{.84 g N}{{\text{O}}_{\text{2}}}\]                                


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