BCECE Engineering BCECE Engineering Solved Paper-2015

  • question_answer
    At constant pressure, the ratio of increase in volume of an ideal gas per degree rise in kelvin temperature to its original volume is

    A) \[{{T}^{2}}\]                                      

    B) \[\frac{1}{T}\]

    C) \[{{T}^{3}}\]                                      

    D) \[T\]

    Correct Answer: B

    Solution :

    According to ideal gas law, \[pV=RT\Rightarrow V=\left( \frac{R}{P} \right)T\] \[V\propto T\] (at constant pressure). Hence,                  \[\frac{{{V}_{1}}}{{{V}_{2}}}=\frac{{{T}_{1}}}{{{T}_{2}}}\] \[\Rightarrow \]               \[\frac{{{V}_{2}}}{{{V}_{1}}}=\frac{-{{T}_{2}}}{{{T}_{1}}}\]                                             ? (i)          where, \[{{V}_{2}}\] is the final volume. \[\frac{{{V}_{2}}}{{{V}_{1}}}-1=\frac{{{T}_{2}}}{{{T}_{1}}}-1\] \[\Rightarrow \]               \[\frac{{{V}_{2}}-{{V}_{1}}}{{{V}_{1}}}=\frac{{{T}_{2}}-{{T}_{1}}}{{{T}_{1}}}\]      \[[\because {{T}_{2}}-{{T}_{1}}=1K]\] \[\Rightarrow \]                               \[\frac{{{V}_{2}}-{{V}_{1}}}{{{V}_{1}}}=\frac{1}{{{T}_{1}}}=\frac{1}{T}\]


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