A) \[\text{225}0\text{ N}\]
B) 2000 N
C) \[\text{15}00\text{N}~~\]
D) \[\text{1}000\text{N}\]
Correct Answer: A
Solution :
Area of cross-section of the tube. \[a={{10}^{-2}}{{m}^{2}}\]Speed of stream of water = 15 m/s V = Volume of water coming out per second from the tube \[=a\times v=15\times {{10}^{-2}}{{m}^{3}}{{s}^{-1}}\] Also, we know that density of water striking the wall per second, then \[m=pV={{10}^{3}}\times 15\times {{10}^{-2}}kg{{s}^{-1}}=150kg{{s}^{-1}}\] As on hitting the wall, water does not reobound. So F = change in momentum per second = mass of water flowing out per second \[\times \] velocity = 150 x 15 = 2250 N
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