A) \[\text{3}00\]
B) \[\text{5}00\]
C) \[\text{2}00\]
D) \[\text{1}00\]
Correct Answer: B
Solution :
The power gain is defined as the ratio of change in output to the change in input power. Since. P = VI Therefore, Power gain = Current gain \[\times \] Voltage gain \[\text{= }\!\!\beta\!\!\text{ }\!\!\times\!\!\text{ }\!\!\beta\!\!\text{ }\left( \frac{{{\text{R}}_{\text{out}}}}{{{\text{R}}_{\text{in}}}} \right)\text{=}{{\text{ }\!\!\beta\!\!\text{ }}^{\text{2}}}\left( \frac{{{\text{R}}_{\text{out}}}}{{{\text{R}}_{\text{in}}}} \right)\] Given, \[\text{ }\!\!\beta\!\!\text{ =10,}{{\text{R}}_{\text{in}}}\text{=20 k }\!\!\Omega\!\!\text{ }\]and\[{{\text{R}}_{\text{out}}}\text{=100 k }\!\!\Omega\!\!\text{ }\] \[\therefore \] Power gain \[={{(10)}^{2}}\left( \frac{100}{20} \right)=100\times 5=500\]
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