A) (5/2,-1)
B) -1,5/2)
C) (3/2, -1)
D) None of these
Correct Answer: A
Solution :
Let\[(h,k)\] be the mid-point of the chord \[2x+y-4=0\]of the parabola \[{{y}^{2}}=4x\]. Then, its equation is \[ky-2(x+h)={{k}^{2}}-4h\] [using \[T=S'\]] \[\Rightarrow \] \[2x-ky+{{k}^{2}}-2h=0\] ? (i) Eq. (i) and \[2x+y-4=0\]represent the same line. \[\therefore \] \[-K=1\]AND \[{{k}^{2}}-2h=-4\] \[\Rightarrow \] \[k=-1,h=\frac{5}{2}\] Hence, the required mid-point is \[\left( \frac{5}{2},-1 \right)\]
You need to login to perform this action.
You will be redirected in
3 sec
