BCECE Engineering BCECE Engineering Solved Paper-2015

  • question_answer
    For all \[n\in N,{{7}^{2n}}-48n-1\] is divisible by

    A) 25                                         

    B) 26

    C) 1234                     

    D)  2304

    Correct Answer: D

    Solution :

    \[{{7}^{2n}}-48n-1\] \[={{(1+48)}^{n}}-48n-1\] \[{{=}^{n}}\,{{C}_{2}}\times {{48}^{2}}+{{\,}^{n}}{{C}_{3}}\times {{48}^{3}}+...+{{\,}^{n}}{{C}_{n}}\times {{48}^{n}}\] \[\Rightarrow \]\[{{7}^{2n}}-48n-1\]is divisible by \[\text{4}{{\text{8}}^{\text{2}}}\text{,i}\text{.e}\text{. 2304}\]


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