BCECE Engineering BCECE Engineering Solved Paper-2014

  • question_answer
    The empirical formula of a non-electrolyte is\[\text{C}{{\text{H}}_{\text{2}}}\text{O}\]. A solution containing 6g of the compound exerts the same osmotic pressure as that of 0.05 M glucose solution at the same temperature. The molecular formula of the compound is

    A) \[{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{4}}}{{\text{O}}_{\text{2}}}\]                

    B) \[{{\text{C}}_{3}}{{\text{H}}_{6}}{{\text{O}}_{3}}\]

    C) \[{{\text{C}}_{5}}{{\text{H}}_{10}}{{\text{O}}_{5}}\]                       

    D) \[{{\text{C}}_{4}}{{\text{H}}_{8}}{{\text{O}}_{4}}\]

    Correct Answer: D

    Solution :

    Solutions having same osmotic pressure, at a given temperature, have same concentration. Concentration of compound = concentration of glucose \[\frac{6}{M\times 1}=0.05\] \[M=\frac{6}{0.05}=120\] \[(C{{H}_{2}}O)=12+2+16=30\] \[\text{n =}\frac{\text{molecular mass}}{\text{empirical formula mass}}=\frac{120}{30}=4\] Hence, molecular formula \[{{(C{{H}_{2}}O)}_{4}}={{C}_{4}}{{H}_{8}}{{O}_{4}}\]


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