BCECE Engineering BCECE Engineering Solved Paper-2014

  • question_answer
    The product(s) formed when \[{{H}_{2}}{{O}_{2}}\] reacts with disodium hydrogen phosphate is

    A) \[{{P}_{2}}{{O}_{5}}.N{{a}_{3}}P{{O}_{4}}\]         

    B) \[N{{a}_{2}}HP{{O}_{4}}.{{H}_{2}}{{O}_{2}}\]

    C) \[Na{{H}_{2}}P{{O}_{4}},{{H}_{2}}O\]    

    D) \[N{{a}_{2}}HP{{O}_{4}}.{{H}_{2}}O\]

    Correct Answer: B

    Solution :

    \[{{H}_{2}}{{O}_{2}}\]form addition product with disodium hydrogen phosphate. \[{{\text{H}}_{\text{2}}}{{\text{O}}_{\text{2}}}\text{+N}{{\text{a}}_{\text{2}}}\text{HP}{{\text{O}}_{\text{2}}}\xrightarrow[{}]{{}}\underset{\text{addition product}}{\mathop{\text{N}{{\text{a}}_{\text{2}}}\text{HP}{{\text{O}}_{\text{4}}}\text{.}{{\text{H}}_{\text{2}}}{{\text{O}}_{\text{2}}}}}\,\]


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