A) \[p{{K}_{a}}-\log 2\]
B) \[p{{K}_{a}}\]
C) \[p{{K}_{a}}+2\]
D) \[p{{K}_{a}}+\log 2\]
Correct Answer: D
Solution :
Initiallly \[\text{ }\!\![\!\!\text{ C}{{\text{H}}_{\text{3}}}\text{COONa }\!\!]\!\!\text{ = 0}\text{.1mol}\] \[\text{ }\!\![\!\!\text{ C}{{\text{H}}_{3}}\text{COOH }\!\!]\!\!\text{ = 0}\text{.1mol}\] When \[\text{0}\text{.1mol C}{{\text{H}}_{\text{3}}}\text{COONa}\]is added. \[\text{ }\!\![\!\!\text{ C}{{\text{H}}_{3}}\text{COONa }\!\!]\!\!\text{ = 0}\text{.1+ 0}\text{.1= 0}\text{.2mol}\] \[\text{pH = p}{{\text{K}}_{\text{a}}}\text{+log}\frac{\text{ }\!\![\!\!\text{ salt }\!\!]\!\!\text{ }}{\text{ }\!\![\!\!\text{ acid }\!\!]\!\!\text{ }}\] \[\text{= p}{{\text{K}}_{a}}+\log \frac{02}{0.1}=p{{K}_{a}}+\log 2\]
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