A) an aldehyde
B) a orimary alcohol
C) a secondary alcohol
D) a ketone
Correct Answer: B
Solution :
Because the difference in mass between \[\text{C}{{\text{H}}_{2}}\text{OH}\] group and ?COOH group is 14, Thus the compound which undergoes oxidation is a primary alcohol. \[(-C{{H}_{2}}OH\] is the functional group of primary alcohols.) \[\underset{\text{primary alcohol}}{\mathop{\underset{\text{(R+31)}}{\mathop{\text{RC}{{\text{H}}_{\text{2}}}\text{OH}}}\,}}\,\xrightarrow{\text{ }\!\![\!\!\text{ O }\!\!]\!\!\text{ }}\underset{\text{acid}}{\mathop{\underset{\text{(R+45)}}{\mathop{\text{RCOOH}}}\,}}\,\]
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