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BCECE Engineering BCECE Engineering Solved Paper-2014

  • question_answer
     Given that \[\text{dE }=\text{ TdS }-\text{ pdV}\] and \[\text{H }=\text{ E }+\text{ pV}\]. Which one of the following relations is true?

    A) \[~\text{dH}=\text{ TdS }-\text{ Vdp}\]    

    B) \[~\text{dH}=\text{SdT}+\text{ Vdp}\]

    C) \[\text{dH}=-\text{SdT}-\text{Vdp}\]    

    D) \[\text{dH }=\text{ dE }-\text{ pdV}\]

    Correct Answer: A

    Solution :

    Given, \[dE=TdS-pdV\]                                                ? (i) \[H=E+pV\]                                                        ? (ii) Differentiating Eq. (ii) \[dH=dE+pdV+Vdp\]                                     ? (iii) From Eq.(i) and (iii),we get \[dH=Tds-Vdp\]


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