BCECE Engineering BCECE Engineering Solved Paper-2014

  • question_answer
    An electric bulb is made of tungsten filament  of resistance \[R\Omega \]. It is marked 100W and 230 V. Then, the value of R is

    A) 300 \[\Omega \]                              

    B) 529 \[\Omega \]  

    C) 739 \[\Omega \]                              

    D) 100\[\Omega \]

    Correct Answer: B

    Solution :

    Power \[P={{V}_{i}}=\frac{{{V}^{2}}}{R}\] \[R=\frac{{{V}^{2}}}{P}=\frac{{{(230)}^{2}}}{100}=529\Omega \]


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