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BCECE Engineering BCECE Engineering Solved Paper-2014

  • question_answer
    As shown in the experimental setup, two cells with the same emf E and different internal resistance \[{{r}_{1}}\] and \[{{r}_{2}}\] are connected in series to an external resistance R Value of R so that the potential difference across the first cell be zero, is

    A) \[{{r}_{1}}+{{r}_{2}}\]                    

    B) \[\frac{{{r}_{1}}}{{{r}_{2}}}\]

    C) \[{{r}_{1}}-{{r}_{2}}\]

    D) \[{{r}_{1}}{{r}_{2}}\]

    Correct Answer: C

    Solution :

    \[i=\frac{2E}{R+{{r}_{1}}+{{r}_{2}}}\] \[i{{r}_{2}}+iR=E\] \[2{{r}_{2}}+2R=R+{{r}_{1}}+{{r}_{2}}\text{or R = }{{\text{r}}_{1}}-{{r}_{2}}\]


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