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BCECE Engineering BCECE Engineering Solved Paper-2014

  • question_answer
    When a radioactive isotope \[_{88}{{R}^{228}}\]decays in 5 series by the emission of \[3\alpha \]-particles and P--\[\beta \]-particles, the mass number of the isotope finally formed is

    A) 83                                          

    B) 72

    C) 216                                        

    D) 228

    Correct Answer: C

    Solution :

    Decrease in mass number due to emission of \[3\alpha \]-particles and \[\beta \]-particles =3x4=12 Decrease in change number in the process =3x2-1=5 Therefore, A=228 -12 =216


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