BCECE Engineering BCECE Engineering Solved Paper-2014

  • question_answer
    Moment of inertia of wheel about the axis of 4 rotation is 3 MKS units. Its kinetic energy will be 600 J, if period of rotation is (in seconds)

    A) \[\pi \]                                 

    B) \[\frac{\pi }{5}\]

    C) \[\frac{\pi }{10}\]            

    D) \[2\pi \]

    Correct Answer: C

    Solution :

    \[E=\frac{1}{2}/{{\omega }^{2}}\] \[\omega =\sqrt{\frac{2E}{l}}=\sqrt{\frac{2\times 600}{3}}=20\] \[\omega =\frac{2\pi }{T}=20\Rightarrow T=\frac{\pi }{10}\]                                


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