BCECE Engineering BCECE Engineering Solved Paper-2014

  • question_answer
    An electron and a photon have equal energy. Then\[{{E}_{K}}\].the ratio of wavelengths of photon and electron is \[\left( \frac{{{\lambda }_{\text{photon}}}}{{{\lambda }_{\text{electron}}}} \right)\]

    A) \[\sqrt{\frac{{{E}_{K}}}{2}}\]                      

    B) \[\frac{1}{\sqrt{2{{E}_{K}}}}\]

    C) \[\frac{2}{\sqrt{{{E}_{K}}}}\]                      

    D) \[\frac{\sqrt{3{{E}_{K}}}}{2}\]

    Correct Answer: C

    Solution :

    \[{{\lambda }_{\text{photon}}}=\frac{hc}{{{E}_{k}}}\] \[{{\lambda }_{\text{electron}}}=\frac{h}{\sqrt{2m{{E}_{k}}}}\] \[\frac{{{\text{ }\!\!\lambda\!\!\text{ }}_{\text{photon}}}}{{{\text{ }\!\!\lambda\!\!\text{ }}_{\text{electron}}}}\text{=}\frac{\text{1}}{\sqrt{{{\text{E}}_{\text{k}}}}}\]


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