A) 7
B) 8
C) 9
D) 10
Correct Answer: D
Solution :
In a binomial distribution, mean, \[np=10\] and variance, \[npq=5\] \[\therefore \] \[10\times q=5\Rightarrow q=\frac{1}{2}\] \[\Rightarrow \] \[p=1-q=1-\frac{1}{2}=\frac{1}{2}\] Let x be the mode. Then, \[np+q>x>np-q\] \[\Rightarrow \] \[10+\frac{1}{2}>x>10-\frac{1}{2}\] \[\Rightarrow \] \[\frac{21}{2}>x>\frac{19}{2}\Rightarrow 9.5<x<1.05\] Hence, option (d) is correct.
You need to login to perform this action.
You will be redirected in
3 sec
