BCECE Engineering BCECE Engineering Solved Paper-2014

  • question_answer
    The value of \[\left( \frac{^{50}{{C}_{0}}}{1}+\frac{^{50}{{C}_{2}}}{3}+.....+\frac{^{50}{{C}_{50}}}{51} \right)\] is

    A) \[\frac{{{2}^{50}}}{51}\]                                               

    B) (b) \[\frac{{{2}^{50}}-1}{51}\]

    C) \[\frac{{{2}^{50}}-1}{50}\]                           

    D) None of these

    Correct Answer: A

    Solution :

                    \[\left( \,\frac{^{50}{{C}_{0}}}{1}+\frac{^{50}{{C}_{2}}}{3}+......+\frac{^{50}{{C}_{50}}}{51} \right)\] \[=\left( \frac{1}{1}+\frac{50\times 49}{3\times 2!}+....+\frac{1}{51} \right)\] \[=\frac{1}{51}\left( \frac{51}{1!}+\frac{51\times 50\times 49}{3!}+.....+1 \right)\]\[=\frac{1}{51}({{\,}^{51}}{{C}_{1}}{{+}^{51}}{{C}_{3}}+...{{+}^{51}}{{C}_{51}})\] \[=\frac{1}{51}{{2}^{51-1}}=\frac{{{2}^{50}}}{51}\]


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