A) NaCI
B) NaH
C) LiH
D) HCOONa
Correct Answer: B
Solution :
In Nelsons cell, \[{{H}_{2}}\]gas is liberated at cathode wheres \[C{{l}_{2}}\]gas is liberated at anode, on electrolysis of solution of NaCI. \[NaClN{{a}^{+}}+C{{l}^{-}}\] \[{{H}_{2}}O{{H}^{+}}+O{{H}^{-}}\] at cathode \[{{H}^{+}}+{{e}^{-}}\xrightarrow{{}}H\] \[H+H\xrightarrow{{}}{{H}_{2}}\uparrow \] at anode \[C{{l}^{-}}\xrightarrow{{}}Cl+{{e}^{-}}\] \[Cl+Cl\xrightarrow{{}}C{{l}_{2}}\uparrow \]You need to login to perform this action.
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