A) 8
B) 16
C) 24
D) 32
Correct Answer: B
Solution :
We know that, only even prime is 2. Then, \[{{(2)}^{2}}-\lambda (2)+12=0\] \[\Rightarrow \] \[\lambda =8\] ...(i) and \[{{x}^{2}}+\lambda x+\mu =0\] has equal roots. \[\therefore \] \[{{\lambda }^{2}}-4\mu =0\] or \[{{(8)}^{2}}-4\mu =0\] [from Eq. (i)] \[\therefore \] \[\mu =16\]You need to login to perform this action.
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