A) \[n\]times
B) \[{{n}^{2}}\]times
C) \[2n\]times
D) \[\sqrt{n}\]times
Correct Answer: B
Solution :
We know that, \[KE=\frac{{{p}^{2}}}{2m}\] i.e., \[KE\propto {{p}^{2}}\] If p is increased n times, then KE will increased by \[{{n}^{2}}\]times.
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